YASH CLASSES
CHEMICAL REACTIONS AND EQUATIONS
NCERT INTEXT QUESTIONS AND ANSWERS
INTEXT QUESTIONS
[ page 6]
1. Why should magnesium ribbon be
cleaned before burning in air?
Ans. Magnesium ribbon should be cleaned before burning in air so that unwanted impurities are removed and we burn only pure magnesium metal. when Mg burn in air combines with oxygen
give magnesium oxide [MgO].
2Mg (s) + O2 (g) → 2MgO (S)
(i)Hydrogen + Chlorine
→ Hydrogen chloride
Ans
. H2 (g)+ Cl2
(g)
→ 2HCI (g)
(ii)Barium chloride + Aluminium sulphate → Barium sulphate +
Aluminium chloride
Ans- 3 BaCl2 (s) + Al2(SO4)3 (s) → 3BaSO4 (s)+
2AICI3(s)
(iii) Sodium Water Sodium Hydroxide Hydrogen
Ans
. 2 Na(s) +2 H2O(l) → 2NaOH
(l) +
H2 (g)
(i) Solutions of barium chloride
and sodium sulphate in water react to give insoluble barium sulphate
and the solution of sodium
chloride.
(ii) Sodium hydroxide solution (in
water) reacts with hydrochloric acid solution (in water) to produce
sodium chloride solution and water.
Ans. (i) BaCl2 (aq) + Na2SO4 (aq) → BaSO4 (s)
+ 2NaCl(aq)
(ii) NaOH (aq)
+ HCl (aq) → NaCl(aq) + H2O (l)
1. A solution of a substance X is used for white-washing [ page 10]
(i) Name
the substance 'X
and write its formula.
(ii)
Write the reaction of the
substance X named in above with water.
Ans. X is quick lime, CaO.
(ii) CaO(s) + H₂O (l) →
Ca(OH)2 (aq)
Quick lime Slaked lime or
Calcium hydroxide
2. Why is the amount of gas
collected in one of the test tubes in Activity (1.7) (Textbook) double of
the amount collected in the other Name this
gas.
Ans. In activity (1.7) water is
electrolysed to give H, gas at one electrode and O, gas at the other electrode
according
to the given chemical reaction: 2H₂O(l) → 2H2(g) + O2(g)
Thus two molecules of water on electrolysis give 2 molecules of hydrogen gas and one molecule of oxygen gas or the amount of hydrogen gas collected would be double than that of oxygen gas.
1. Why does the colour of copper sulphate solution change when an iron nail
is dipped in it ? [ page13]
Ans. When an iron mail is dipped in copper sulphate solution, it becomes
brownish in colour and
colour of
copper sulphate fades due to the following reaction
Fe
(s) +
CuSO4 (aq) → FeS04
(aq) + Cu (s)
Copper sulphate
In this reaction iron has replaced copper
from its solution. Thus amount of per sulphate decreases
and its colour fades.
2. Give an example of a double displacement
reaction other than one given in Activity 1.10.
Ans. When a solution of hydrochloric acid is
added to a solution of lend nitrate, a white precipitate of lead
chloride is formed.
Pb(NO3 )2
(aq)
+ 2HCl(aq) → PbCl2 (s )+ 2HNO3 (aq)
Lead nitrate Lead chloride
Pb2 +
ions from lead nitrate combine with 2Cl-
ions from hydrochloric acid and a precipitate of
lead chloride is formed. Thus there is an exchange of ions
between the two reactants for example
lead nitrate and hydrochloric acid, and thus this reaction is a double displacement reaction.
No comments:
Post a Comment